Optimal. Leaf size=135 \[ -\frac{e^{2 a} 2^{-\frac{m}{2}-\frac{7}{2}} \left (-b x^2\right )^{\frac{1}{2} (-m-1)} (e x)^{m+1} \text{Gamma}\left (\frac{m+1}{2},-2 b x^2\right )}{e}-\frac{e^{-2 a} 2^{-\frac{m}{2}-\frac{7}{2}} \left (b x^2\right )^{\frac{1}{2} (-m-1)} (e x)^{m+1} \text{Gamma}\left (\frac{m+1}{2},2 b x^2\right )}{e}-\frac{(e x)^{m+1}}{2 e (m+1)} \]
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Rubi [A] time = 0.147643, antiderivative size = 135, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 3, integrand size = 16, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.188, Rules used = {5340, 5329, 2218} \[ -\frac{e^{2 a} 2^{-\frac{m}{2}-\frac{7}{2}} \left (-b x^2\right )^{\frac{1}{2} (-m-1)} (e x)^{m+1} \text{Gamma}\left (\frac{m+1}{2},-2 b x^2\right )}{e}-\frac{e^{-2 a} 2^{-\frac{m}{2}-\frac{7}{2}} \left (b x^2\right )^{\frac{1}{2} (-m-1)} (e x)^{m+1} \text{Gamma}\left (\frac{m+1}{2},2 b x^2\right )}{e}-\frac{(e x)^{m+1}}{2 e (m+1)} \]
Antiderivative was successfully verified.
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Rule 5340
Rule 5329
Rule 2218
Rubi steps
\begin{align*} \int (e x)^m \sinh ^2\left (a+b x^2\right ) \, dx &=\int \left (-\frac{1}{2} (e x)^m+\frac{1}{2} (e x)^m \cosh \left (2 a+2 b x^2\right )\right ) \, dx\\ &=-\frac{(e x)^{1+m}}{2 e (1+m)}+\frac{1}{2} \int (e x)^m \cosh \left (2 a+2 b x^2\right ) \, dx\\ &=-\frac{(e x)^{1+m}}{2 e (1+m)}+\frac{1}{4} \int e^{-2 a-2 b x^2} (e x)^m \, dx+\frac{1}{4} \int e^{2 a+2 b x^2} (e x)^m \, dx\\ &=-\frac{(e x)^{1+m}}{2 e (1+m)}-\frac{2^{-\frac{7}{2}-\frac{m}{2}} e^{2 a} (e x)^{1+m} \left (-b x^2\right )^{\frac{1}{2} (-1-m)} \Gamma \left (\frac{1+m}{2},-2 b x^2\right )}{e}-\frac{2^{-\frac{7}{2}-\frac{m}{2}} e^{-2 a} (e x)^{1+m} \left (b x^2\right )^{\frac{1}{2} (-1-m)} \Gamma \left (\frac{1+m}{2},2 b x^2\right )}{e}\\ \end{align*}
Mathematica [A] time = 0.615218, size = 152, normalized size = 1.13 \[ -\frac{2^{\frac{1}{2} (-m-7)} x \left (-b^2 x^4\right )^{\frac{1}{2} (-m-1)} (e x)^m \left ((m+1) (\cosh (2 a)-\sinh (2 a)) \left (-b x^2\right )^{\frac{m+1}{2}} \text{Gamma}\left (\frac{m+1}{2},2 b x^2\right )+(m+1) (\sinh (2 a)+\cosh (2 a)) \left (b x^2\right )^{\frac{m+1}{2}} \text{Gamma}\left (\frac{m+1}{2},-2 b x^2\right )+2^{\frac{m+5}{2}} \left (-b^2 x^4\right )^{\frac{m+1}{2}}\right )}{m+1} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.092, size = 0, normalized size = 0. \begin{align*} \int \left ( ex \right ) ^{m} \left ( \sinh \left ( b{x}^{2}+a \right ) \right ) ^{2}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.83331, size = 512, normalized size = 3.79 \begin{align*} -\frac{8 \, b x \cosh \left (m \log \left (e x\right )\right ) +{\left (e m + e\right )} \cosh \left (\frac{1}{2} \,{\left (m - 1\right )} \log \left (\frac{2 \, b}{e^{2}}\right ) + 2 \, a\right ) \Gamma \left (\frac{1}{2} \, m + \frac{1}{2}, 2 \, b x^{2}\right ) -{\left (e m + e\right )} \cosh \left (\frac{1}{2} \,{\left (m - 1\right )} \log \left (-\frac{2 \, b}{e^{2}}\right ) - 2 \, a\right ) \Gamma \left (\frac{1}{2} \, m + \frac{1}{2}, -2 \, b x^{2}\right ) + 8 \, b x \sinh \left (m \log \left (e x\right )\right ) -{\left (e m + e\right )} \Gamma \left (\frac{1}{2} \, m + \frac{1}{2}, 2 \, b x^{2}\right ) \sinh \left (\frac{1}{2} \,{\left (m - 1\right )} \log \left (\frac{2 \, b}{e^{2}}\right ) + 2 \, a\right ) +{\left (e m + e\right )} \Gamma \left (\frac{1}{2} \, m + \frac{1}{2}, -2 \, b x^{2}\right ) \sinh \left (\frac{1}{2} \,{\left (m - 1\right )} \log \left (-\frac{2 \, b}{e^{2}}\right ) - 2 \, a\right )}{16 \,{\left (b m + b\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (e x\right )^{m} \sinh ^{2}{\left (a + b x^{2} \right )}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (e x\right )^{m} \sinh \left (b x^{2} + a\right )^{2}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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